Find the enthalpy AH (KJ) in the reaction CH469) + 4C12(g) ==> CC140) + 4HCLG) C(s) + 2H2(g) ==> CH4(g) Where AHF = -79.4 KJ C(s) + 2Cl2(g) ==> CCl4( where AH = = -135.4 KJ 1/2 H2(s) + 1/2 Cl2(g) ==> HCIG) where AH 4 = -92.3 KJ Select one: O a. 0.430 O b.-4.30 O c. 430 O d. -430