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Find the equation for the plane through the point Po = (0,2,-5) and normal to the vector n = 3i-6j-k. Choose the correct answer
Find the equation for the plane through the point Po = (0,2,-5) and normal to the vector n = 3i-6j-k. Choose the correct answer below. OA. 3x-6y-z=-7 OB. 3x-6y-z=0 OC. 3x-6(y+2)-(z-5)=0 OD. (x+3)+2(y-6)-5(z-1)=-7
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