Find the equation for the tangent plane and the normal line at the point Po(1,1,2) on the surface 3x2 + y2 + 472 = 20. Using a coefficient of 3 for x, the equation for the tangent plane is Find the equations for the normal line. Let x = 1 + 6t. X = Z = (Type expressions using t as the variable.)Find an equation for the plane that is tangent to the given surface at the given point. z=y'yx (1,5,2) Find the equation for the tangent plane to the surface 2 = fly -x at the point (1,5,2). Use a coefcient of 1 for x. =0