Find the equation of the tangent line to the curve f(x) = 4 sec(x) - 8 at the point (, f ( ) ). y= xsec(x)-((2pisec(x))/3))-8x+(4pi/3)+(fpi)/6 E Help Entering Answers Preview My Answers Submit Answers Show me another Results for this submission Answer Entered Result Message Preview 4xsec(x)-((2pisec(x))/3))-8x+(4pi Function 'sec' is not allowed in this incorrect /3)+(fpi)/6 context