Find the equation of the tangent line to the curve Y = (x-1)^3 (x+2)^2 at the point (2,16).The equation of the tangent line to the curve at the given point is Y =

at Find the equation of the tangent line to the curve y = (x - 1) (x + 2) at the point (2, 16). The equation of the tangent line to the curve at the given point is y = s 8 (Type an expression using x as the variable.)