Find the first and second derivative of the following function in terms of the parameters $c_1$ and $c_2.$

$y=c_{1}x{c}_2{x}^4$

$y^{\text{'}}=$

$y^{\text{'}\text{'}}=$

Find a linear second$-$order differential equation $F(x,y,y^{\text{'}},y^{\text{'}\text{'}})=0$ for which $y=c_{1}x{c}_2{x}^4$ is a two$-$parameter family of solutions. Make sure that your equation is free of the arbitrary parameters $c_1$ and $c_2.($Use $yp$ for $y^{\text{'}}$ and $ypp$ for $y^{\text{'}\text{'}}.)$

$$

$=0$