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Find the focus, directrix. vertex and axis of symmetry for the parabola 12{y+ 1} = [x + 239 Be sure to enter each answer in
Find the focus, directrix. vertex and axis of symmetry for the parabola 12{y+ 1} = [x + 239 Be sure to enter each answer in the appropriate format. Hint: What is the appropriate notation for a line or a point? Graph the parabola. Include the directrix and focus with your graph. ClearAll Draw: //\ Q Determine whether this 1'5 a parabola: y = 5:2 + 20:: + 11 . '53 Farah-Ola C} Not a parabola 64 If it is a parabola, write the equation in standard form: (1; ME = 4,51,: h} or (I M2 = daily k). CIthenrvl'iser leave the rest blank. h=-2 '0' Determine whether the given equation is a parabola: I 2 2y: . El Farab-ola '3' Not a parabola "as? If it is a parabola, write the equation in standard form: [3; ME = 4:43 h] or {I h)2 = 413w k). l'Jther'lrlriser leave the rest blank. 13': '9 55 Find the equation for the parabola that has its focus at (1' 4) and has directrix x = T The equation is: Find the coordinates of the vertex and the focus for the parabola given by the following equation: Ig+x 24y lEr =l] Round all answers to 2 place: after the decimal point, if necessary. Coordinates of the vertex: [II II, I II} Coordinates of the focus: (l. l. l I} An arch is in the shape of a parabola. It has a span of 334 feet and a maximum height of 32 feet. Find the equation of the parabola [assuming the origin is halfway between the arch's feet]. :1 Determine the height of the arch 11 feet from the center. - _
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