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Find the location of the center, vertices, and foci for the hyperbola described by the equation. 9) ( x - 3)2 ( y + 4)2

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Find the location of the center, vertices, and foci for the hyperbola described by the equation. 9) ( x - 3)2 ( y + 4)2 9) 49 36 A) Center: ( , -4); Vertices: (-4, -4) and (10, -4); Foci: ( - V85, -4) and ( + \\85, -4) B) Center: ( , -4); Vertices: (-4, ) and (10, ); Foci: ( - \\85, ) and ( + \\85, ) C) Center: ( , -4); Vertices: (-3, -4) and (11, -4); Foci: ( + \\85, -3) and (-3 + \\85, -3) D) Center: (-3, 4); Vertices: (-10, 4) and (4, 4); Foci: (-3- 85, 4) and (-3 + \\85, 4) Find the focus and directrix of the parabola with the given equation. 10) x2 = 36y 10) A) focus: (9, 0) B) focus: (0, -9) C) focus: (9, 0) D) focus: (0, 9) directrix: y = 9 directrix: x = - 9 directrix: x = 9 directrix: y = -9 Find the standard form of the equation of the parabola using the information given. 11) Focus: (0, - 14); Directrix: y = 14 11) A) x2 - -56y B) y2 = -56x C) y2 = - 14x D) x2 - 56y 12) Focus: (6, 0); Directrix: x = -6 12) A) x2 = 24y B) y2 = -24x C) y2 = 6x D) y2 = 24x Convert the equation to the standard form for a parabola by completing the square on x or y as appropriate. 13) y2 - 6y - 6x + 3 = 0 13) A) (y - 3)2 = 6(x - 1) B) (y - 3)2 = 6(x + 1) C) (y + 3)2 = -6(x + 1) D) (y + 3)2 = 6(x + 1) Determine the direction in which the parabola opens, and the vertex. 14) y2 - 12y - x + 41 = 0 14) A) Opens downward; (-6, - 5) B) Opens downward; ( , - 5) C) Opens to the left; (- 5, -6) D) Opens to the right; (5, 6) Use the vertex and the direction in which the parabola opens to determine the relation's domain and range. 15) y2 - 12y - x + 32 = 0 15) A) Domain: (- xe, se) B) Domain: (- 30, 2x) C) Domain: (-4, *] D) Domain: (- 20, 4) Range: (- so, ) Range: (- >, 4] Range: ( - se, x) Range: (- 2, xx) Identify the equation without completing the square. 16) 4x2 + 3y2 + 5x - 3y = 0 16) A) circle B) parabola C) hyperbola D) ellipse

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