Find the net torque on the wheel in the figure below about the axle through O, taking a = 9.00 cm and b = 25.0 cm. (Assume that the positive direction is counterclockwise.)

N . m 10.0 N 30.00 O 12.0 N 9.00 NGiven ! - a = 9.0 cm = 0.09 m Z 10 ON b = 25 cm = 0.25 m. Torre due to lo N: 7 30 121 To = 10 x b = 10 * 0.25 = 2.5 N'm To = 2.5 Nm ( clockwine). 9 N To rique due to gN 1- To = 9xb = 9x.215 Tg = 2.2,5 NM ( clockwise ) Torque thee to 12NI- since IIN is not & perpendicular to a so tape its component along tangent to small circle F PRO = 12 CON 30 To = 12 con 30x a 12 COA 30X 809 Ti = 0. 9350 7 Nm( counterclockwise ) Total toravine = - The Ta + Tiz 2.5 +225 - 2. 9350 Total torique = -3. 815. N-m. (clockwine ) Tongue due to 12 N:7 12 N Force in tangential so e Th = 12x9 = 12 x 0.09 = 108 Nm ( counter clockw Total torque = - 2.25 - 2.5 + 1:08 2 - 3.67 Net torique = 3.67 in Clockwise direction