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Find the percent of area under a normal curve between the mean and - 1.10 standard deviations from the mean. (Mote that positive indicates above

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Find the percent of area under a normal curve between the mean and - 1.10 standard deviations from the mean. (Mote that positive indicates above the mean, while negative indicates below the mean.) Click here to see page 1 of the table for areas under the standard normal curve. Click here to see page 2 of the table for areas under the standard normal curve. The percentage of area under a normal curve between the mean and - 1.10 standard deviations is D%. (Round to the nearest tenth as needed.) Find the percent of area under a normal curve between the mean and the given number of standard deviations from the mean. (Mote that positive indicates above the mean, while negative indicates below the mean.) -0.40 % (Round to the nearest tenth as nesded.) Find the percent of the total area under the standard normal curve between the following z-scores. Z= - 1.3 and z =0.55 Click here to see page 1 of the table for areas under the standard normal curve. Click here to see page 2 of the table for areas under the standard normal curve. The percent of the total area between z = - 1.3 and z = 0.55 is %. 'Round to the nearest tenth as needed.)Find the percent of the total area under the standard normal curve between the following z-scores. Z= - 1.2 and z= - 0.65 The percent of the total area between z = - 1.2 and z = - 0.65 is (Round to the nearest integer.)A large company employs workers whose IQs are distributed normally with mean 110 and standard deviation 12.5. Management uses this information to assign employees to projects that will be challenging, but not too challenging. What percent of employees would have IQs less than 95' Click here to see page 1 of the table for areas under the standard normal curve. Click here to see page 2 of the table for areas under the standard normal curve. The percentage of employees expected to have IQs less than 95 is%. [Round to the nearest tenth as needed.)

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