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Find the point on the curve y = 3/ 2 for which the tangent line to the curve is perpendicular to the line 128x +

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Find the point on the curve y = 3/ 2 for which the tangent line to the curve is perpendicular to the line 128x + 1, 715y + 383 = 0. Note: Write the exact answer but not the approximate value (For example write but not 0.8) Answer: The point is (x, y) where y =

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