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Find the point(s} that will minizine the distance from (0, 9) to the function f(93) = :32. Let s be the distance from (0, 9)
Find the point(s} that will minizine the distance from (0, 9) to the function f(93) = :32. Let s be the distance from (0, 9) and any point (9:, y) on x) = 3:2 a. What expression would represent the distance 3 in terms of m ? 3: b. Since the square root function is always increasing, to minizine 3 you should minizine $1: $2: .3: f. Uses the 2nd derivative test to determine which critical number is a minimum. (12 (.92) da:2 g. When substituting x1 into the second derivative you get , therefore 5 has a local h. When substitutingxg into the second derivative you get , therefore .9 has a local i. Since 3 and 32 are both even functions (You should check.), 33 is also a local j. Therefore, the points that minizine the distance from (0, 9) to the curve f(x) = m2 in ascending order are... :]
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