Find the regression equation, letting the diameter be the predictor (:1) variable Find the heat predicted circumference of a marble with a diameter nf1.2 cm How does the result compare to the actual circumference of 3.8 cm" Use a signicance level all] 05. Baseball Basketball Golf Soccer Tennis PingPung Volleyball Q Diameter 7.5 24.2 4 4 22 2 7.1 4 1 2|] 7 Circumference 23.6 76.0 13.8 65 7 22 3 12.9 65 I] 3 Click the icon to view the critical values of the Pearson correlation coeicieht r. The regression equation lair} D 01874 + 3 13934 x. (Round to live decimal places as needed ) The best predicted circumference for a diameter of 1.2 cm is cm. (Round to one decimal place as needed) How does the result compare to the adual circumferehce of 3.8 cm'F| O A. Even though 1.2 cm is beyond the scope of the sample diameters. the predicted value yields the actual circumference O B. Even though 1.2 cm is within the scope of the sample diameters, the predicted value yields a very di'erent circumference O C. Since 1.2 cm is withih the scope of the sample diameters. the predicted value yields the actual circumference O D. Since 12 cm is beyond the scope of the sample diameters, the predicted value yields a very dierenl circumference