Find the tangent equation to the given curve that passes through the point (12, 8). Note that due to the t2 in the x equation and the to in the y equation, the equation in the parameter t has more than one solution. This means that there is a second tangent equation to the given curve that passes through a different point. x = 6t2 + 6 y = 4+3 + 4 y = -x + 20 (tangent at smaller t) X y = x-4 (tangent at larger t) Need Help? Read It