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Find the tangent plane to the given surface at the specified point: z= 3y^2 - 2x^2 + x, (2, -1, -3) Please explain each step

Find the tangent plane to the given surface at the specified point:

z= 3y^2 - 2x^2 + x, (2, -1, -3)

Please explain each step I know I need to use the formula (z-z0 = f(x)(x0,y0)(x-x0) + f(y)(x0,y0)(y-y0)) However, I do not know what to plug in or how to get there...

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