Find the value of X that satisfies the following equations (You should clearly show steps about how you get the answer): a) (C372)16-(395E) 16 = (X)16 b) (0010 1000 0000 0111) BCD + (0001 1001 1001 0101) BCD = (X) BCD c) (35)x+ (18)x = (51)x d) (10110.11)5 = (X)15 e) (2404) 10 = (C3A)x f) X = the 15's complement of (2B070) 15 g) X = the Gray code for the binary value (101100) 2 A new university has 3,500 students. It is required to give each student a unique binary code (inside the registration software): a) How many bits would we need? b) If it is anticipated that the number of students will double every 5 years, how many bits would we need after 20 years? c) For the sake of documentation, how many Hex digits would we need to represent these codes (now and after 20 years)? Comment on the number of Hex digits needed as compared to the binary bits needed.