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Find y' and the slope of the tangent line to the graph of the equation below at the indicated point. 2 127+y 3 - X

Find y' and the slope of the tangent line to the graph of the equation below at the indicated point. 2 127+y 3 - X +58 = 0; (4,3) y'= y' (4.3)= (Simplify your answer.)

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