Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Finding derivatives: Use quotient rule to find the derivative of g(x) = 22+5 12+61' Select one: Oa. g'(x) = 20'-30r-52 x2 (2+6)2 Ob. g'(x) =

Finding derivatives:

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
Use quotient rule to find the derivative of g(x) = 22+5 12+61' Select one: Oa. g'(x) = 20'-30r-52 x2 (2+6)2 Ob. g'(x) = 67- -10r-30 12(x+6)2 Oc. q(x) = Ar +18x-r+10r+30 x2 (2+6)2 Od. g(x) =2+613+5x2+30r x2(2+6)2 Oe. g'(x) = 64+10r+30 12 (x+6)2 Clear my choiceFind the slope of the tangent line to the curve .3, = 933% _ 713% at x = 4. Select one: 6) a. 159 O b. 6 O c. 8 0 d. 96 0 e. 43 Clear my choice What is the derivative of f(x) = 6x-2 + 8x3 + 11x + 10+ e ? Select one: O a. -12x + 24x2 + 11 + e" O b. -12x-+ 24x2 + er O c. _12x-3+ 24x' + 11 + e] O d. -12x 3+ 24x2+ er O e. 12x3 + 8x + 11x2 + e] Clear my choiceIf g' (4) = 4 and h' (4) = -1, find f'(4) for f (x) = 5g(x) + 3h(x) + 2. Select one: O a. 19 O b. 27 O c. 23 O d. 25 O e. 17 Clear my choiceFind an equation for the line tangent to given curve _ 2_ y = {1211 3 at a; = 0. Select one: 6) a. y :12x3 O b. y :12x+ 3 O c. y : -12x 3 0 d. y = -12X + 3 0 e. y :12x 9 Clear my choice

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image_2

Step: 3

blur-text-image_3

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Introduction To Probability Models

Authors: Sheldon M Ross

5th Edition

1483276589, 9781483276588

More Books

Students also viewed these Mathematics questions

Question

7. One or other combination of 16.

Answered: 1 week ago

Question

5. It is the needs of the individual that are important.

Answered: 1 week ago