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Five (5) kg min of a hot liquid oil stream is to be cooled from 300 C to 150 C by using ten (10) kg
Five (5) kg min of a hot liquid oil stream is to be cooled from 300 C to 150 C by using ten (10) kg min of cooling water at 25 C in a steady-state, adiabatic heat exchanger, operated at atmospheric pressure. Heat capacities of both oil and water may be assumed constant as Cp.oil = 2.51 kJ kg;' K' and Cp,water 4.184 kJ kg ' K. -1 'gen a) Taking the heat exchanger as your control volume, simplify the general energy balance equation and show that the outlet temperature of cooling water is 70 C. [7] b) Calculate the rate of entropy generation, , in kJ K ' min'. Comment on your answer. [10] =) With respect to a surrounding temperature of To = 25 C, calculate the maximum (ideal) work that can be recovered from the hot oil stream in being cooled from 300 C to 150 C. [5] 1) If the above exchanger is replaced by a reversible heat engine operating with the oil as a heat source and the surrounding at To = 25 C as a cold temperature reservoir, find the amount of work obtained from this heat engine in kJ min'. Comment on your answers in parts 3) and 4)
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