For 3B can you explain in detail how they calculated T values and the final answers? Thank you!

( 5, 0 ) 3. (12 pts) Let T be the triangle with vertices (0, 0) (0,3) and ( ). Let C be the boundary curve of I ; oriented counterclockwise 1(0, 3 ) (a) Let F(x, y) = (312y3, 3x3y?). Calculate fo F . ds. F = D (f (x,y) ) = V ( x 3 3) C2 Thus c ( 5 , 0 ) fF. d's = $ of ds = fly = 0 C C (4 6) F TOC for Line Integrals Since C is a closed curve 7 (t ) = ost51 (b) Calculate fo cos(x)ds r3 ( t ) = - 3Et50 * cos(x )ds = [ cos(x) ds C , + ( 2 + C 3 ( + 3 ) Scos(x)ds = 9 cos(t ). (127 dt = sin(t ) 10= sin(5) C , 43 S cos (x)ds = ) cos (5- 5t) / 252 + 32 dt = 137 134 sin(5- 5+) / 2 - C2 5- sin ( 5 )