For a simple random sample of pulse rates of women (measured in beats per minute), n = 146 and s = 13.5. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.10 signicance level to test the claim that pulse rates of women have a standard deviation equal to 10 beats per minute; see the accompanying JMP display that results from using the original list of pulse rates instead of the summary statistics. (Hint: The bottom three rows of the display provide P-values for a two-tailed test, a left-tailed test, and a right-tailed test, respectively.) What do the results indicate about the effectiveness of using the range rule of thumb with the "normal range" from 60 to 100 beats per minute for estimating o in this case? Assume that the simple random sample is selected from a normally distributed population. 0 Click the icon to view the JMP display. Let 6 denote population standard deviation of the pulse rates of women (in beats per minute). Identify the null and alternative hypotheses. H0:o V H1: 6 V (Type integers or decimals. Do not round.) Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the nal conclusion that addresses the original claim. V the null hypothesis. There V sufcient evidence to V the claim that pulse rates of women have a standard deviation equal to 10 beats per minute. The results indicate that there V signicant evidence that using the range rule of thumb with the "normal range" from 60 to 100 beats per minute for estimating 5 V effective in this case. The accompanying data are the weights (kg) of poplar trees that were obtained from trees planted in a rich and moist region. The trees were given different treatments identified in the accompanying table. Also shown are partial results from using the Bonferroni test with the sample data. Complete parts (a) through (c). @ Click the icon to view the data table of the poplar weights and the Bonferroni results. E) a. Use a 0.10 signicance level to test the claim that the different treatments result in the same mean weight. Determine the null and alternative hypotheses. Ho: V H1: V Determine the test statistic. The test statistic is (Round to two decima places as needed.) Determine the P-value. The Pvalue is . (Round to three decimal places as needed.) What is the conclusion for this hypothesis test at a 0.10 signicance level? Reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. A B. Fail to reject H0. There is insufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. C Fail to reject H0. There is sufficient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. D Reject H0. There is sufcient evidence to warrant rejection of the claim that the four different treatments yield the same mean poplar weight. b. What do the displayed Bonferroni results tell us? With a P-value of , there a signicant difference between the No Treatment and Fertilizer groups. With a P-value of , there V a signicant difference between the No Treatment and Irrigation groups. With a P-value of , there a signicant difference between the No Treatment and Irrigation groups. With a P-value of , there a signicant difference between the No Treatment and Fertilizer and irrigation groups. (Round to three decimal places as needed.) c. Let u1, P21 P3! and M represent the mean amount of the no treatment, fertilizer, irrigation, and fertilizer and irrigation groups, respectively. Use the Bonferroni test procedure with a 0.10 signicance level to test for a signicant difference between the mean amount of the irrigation treatment group and the group treated with both fertilizer and irrigation. Identify the test statistic and the P-value. What do the results indicate? Determine the null and alternative hypotheses. H0: V H1: V The test statistic is (Round to two decima places as needed.) Find the Pvalue. The Pvalue is (Round to three decimal places as needed.) What do the results indicate at a 0.10 significance level? If} A. Fail to reject H0. There is insufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar weight. {"2} B. Fail to reject H0. There is sufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar weight. {"3 C. Reject H0. There is insufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar O C. Reject Ho. There is insufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar weight. O D. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the irrigation treatment group and the group treated with both fertilizer and irrigation yield the same mean poplar weight