For a simple random sample of pulse rates of women (measured in beats per minute), n = 139 and s = 12.9. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.01 significance level to test the claim that pulse rates of women have a standard deviation equal to 10 beats per minute; see the accompanying JMP display that results from using the original list of pulse rates instead of the summary statistics. (Hint: The bottom three rows of the display provide P-values for a two-tailed test, a left-tailed test, and a right-tailed test, respectively.) What do the results indicate about the effectiveness of using the range rule of thumb with the "normal range" from 60 to 100 beats per minute for estimating o in this case? Assume that the simple random sample is selected from a normally distributed population. i Click the icon to view the JMP display. Let o denote population standard deviation of the pulse rates of women (in beats per minute). Identify the null and alternative hypotheses. Ho: 0 (Type integers or decimals. Do not round.) Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There sufficient evidence to the claim that pulse rates of women have a standard deviation equal to 10 beats per minute. The results indicate that there significant evidence that using the range rule of thumb with the "normal range" from 60 to 100 beats per minute for estimating o effective in this case.The test statistic of z = 1.23 is obtained when testing the claim that p # 0. 135. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of a - 0.10, should we reject Ho or should we fail to reject Ho? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. . . . a. This is a test. b. P-value = (Round to three decimal places as needed.) c. Choose the correct conclusion below. O A. Reject Ho. There is not sufficient evidence to support the claim that p # 0.135. O B. Fail to reject Ho. There is not sufficient evidence to support the claim that p # 0. 135. O C. Reject Ho. There is sufficient evidence to support the claim that p # 0.135. O D. Fail to reject Ho. There is sufficient evidence to support the claim that p # 0.135.This question: 1 point(s) possible Submit quiz A random sample of 960 births in New York State included 472 boys, and that sample is to be used for a test of the common belief that the proportion of male births in the population is equal to 0.512. Complete parts (a) through (c). a. In testing the common belief that the proportion of male babies is equal to 0.512, identify the values of p and p. p = P= (Round to three decimal places as needed.) 472 b. For random samples of size 960, what sample proportions of male births are at least as extreme as the sample proportion of 960 -? Select the correct choice below and fill in the answer box(es) within your choice. (Round to three decimal places as needed.) O A. Those that are less than or equal to O B. Those that are less than or equal to and those that are greater than or equal to O C. Those that are both greater than or equal to and less than or equal to O D. .Those that are greater than or equal to 472 c. In using the method of randomization with 1000 resamples, it is found that 235 of them have sample proportions that are at least as extreme as . Using a significance level of 0.10, what 960 should be concluded about the claim that the proportion of male births is equal to 0.512? the claim that the proportion of male births is equal to 0.512. There sufficient evidence to