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For a simple random sample of pulse rates of women (measured in beats per minute), n = 142 and s= 12.3. The normal range of
For a simple random sample of pulse rates of women (measured in beats per minute), n = 142 and s= 12.3. The normal range of pulse rates of adults is typically given as 60 to 100 beats per minute. If the range rule of thumb is applied to that normal range, the result is a standard deviation of 10 beats per minute. Use the sample results with a 0.01 significance level to test the claim that pulse rates of women have a standard deviation equal to 10 beats per minute; see the accompanying JMP display that results from using the original list of pulse rates instead of the summary statistics. (Hint: The bottom three rows of the display provide P-values for a two-tailed test, a left-tailed test, and a right-tailed test, respectively. ) What do the results indicate about the effectiveness of using the range rule of thumb with the "normal range" from 60 to 100 beats per minute for estimating o in this case? Assume that the simple random sample is selected from a normally distributed population. Click the icon to view the JMP display. Let o denote population standard deviation of the pulse rates of women (in beats per minute). Identify the null and alternative hypotheses. H: H1: 0 (Type integers or decimals. Do not round.) Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. the null hypothesis. There sufficient evidence to the claim that pulse rates of women have a standard deviation equal to 10 beats per minute. The results indicate that there significant evidence that using the range rule of thumb with the "normal range" from 60 to 100 beats per minute for estimating o effective in this case.Test Standard Deviation Hypothesized Value 10 Actual Estimate 12.3030 DF 141 Test ChiSquare Test Statistic 213.4243 Min PValue 0.0002 Prob ChiSq .0001
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