For all of the problems 1-8 I only need the correct answer. I do not need an explanation. I will be sure to give the highest rating, thank you!

Question 1: There are 3 boxes below that you will have to choose the correct answer for.

Passes because 10(96) s all high school seniors Passes because 10(150) s all high school seniors Fails because 10(96) > 150\fIn a survey of 150 randomly selected high school student athletes, 96 say they get better grades during their athletic season than when they are technically off-season. Construct and interpret a 95% confidence interval for the true proportion of high school student athletes that get better grades during their athletic season. Check the conditions. Random: ' v 10% .' Independent : ' v' Normal I Large Counts: ' v' In a survey of 150 randomly selected high school student athletes, 96 say they get better grades during their athletic season than when they are technically off-season. Construct and interpret a 95% confidence interval for the true proportion of high school student athletes that get better grades during their athletic season. Point Estimate, p: critical value, z*: standard deviation, op : Margin of Error: Construct a 95% confidence interval for p:As the sample size increases, what happens to the margin of error? 0 Larger {interval gets wider) O Smaller [interval gets narrower) O Stays the Same As the confidence level decreases, what happens to the margin of error? O Larger (interval gets wider) O Smaller (interval gets narrower) O Stays the SameA recent poll found that 432 of the 1200 randomly-selected adults questioned felt that then minimum wage should be raised. Construct a 95% confidence interval to estimate the proportion of the U.S. adults who feel this way. Round confidence intervals to the nearest thousandth.Political parties rely heavily upon polling to measure their support in the electorate. An approval poll is conducted and the candidate is supported by 532 of the 1100 randomly-selected voters who were polled. Construct a 99% condence interval to estimate the proportion of voters who support the candidate. Check the conditions. Random: ' V' 10% I Independent :' v' Normal I Large Counts: ' v Passes because 10(532) s all voters Passes because 10(1100) s all voters Fails because 10(532) > 1100 votersPasses because 532(0.99) 2 10 and 532(1-0.99) 2 10 Passes because 532(0.48) 2 10 and 532(1-0.48) 2 10 Passes because 1100(0.99) 2 10 and 1100(1-0.99) 2 10 Passes because 1100(0.48) 2 10 and 150(1-0.48) 2 10Political parties rely heavily upon polling to measure their support in the electorate. An approval poll is conducted and the candidate is supported by 532 of the 1100 randomly-selected voters who were polled. Construct a 99% confidence interval to estimate the proportion of voters who support the candidate. Round all to three decimal places. Point Estimate, p: critical value, z*: standard deviation, of : Margin of Error: Construct a 95% confidence interval for p:A senator wishes to estimate the proportion of United States voters who favor abolishing the Electoral College. How large a sample is needed in order to be 99% condent that the sample proportion will not differ from the true proportion by more than 5%