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For both trials with a dielectric, graph capacitance vs. area and capacitance vs. separation distance (need to adjust to obtain a straight line-hint inverse). Be
For both trials with a dielectric, graph capacitance vs. area and capacitance vs. separation distance (need to adjust to obtain a straight line-hint inverse). Be sure to include a legend.
Dielectric 1: Paper Area= 100.0 mm K= 3.50 Constance d: Separation Distance: 10.0mm Capacitance (F) Area (mm2) 3.10E-13 100.0 4.69E-13 151.4 6.27E-13 202.3 7.82E-13 252.4 9.27E-13 299.2 10.40E-13 335.6 12.40E-13 400.0 Constant A: Area: 100.0 mm2 Capacitance (F) Separation Distance (mm2) 3.10E-13 10.0 3.46E-13 9.0 3.91E-13 7.9 4.50E-13 6.9 5.15E-13 6.0 6.20E-13 5.0Dielectric 2: Glass Area = _100.0 \"mm2 K: 4.70 Constant (1: Separation Distance: 10.0mm CapaCItance (F) 4.16E 13 100.0 6.30E 13 151.4 8 42E 1 3 202.3 10 50E 13 252.4 12 63E 13 303.6 14 56E13 349.9 16.65E13 400.0 Constant A: Area: _100.0 7mm2 Capac1tance (F) Separation Distance (mm) 4 16E 13 . 4 64E 13 5.1412 13 692E 13 832E 13 6 05E13Step by Step Solution
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