For correcting for hyperopia (using the thin lens equation), you would place the object at _____ and the ____ image at ____.

Group of answer choices

infinity, virtual, the far point.

infinity, real, the near point.

infinity, virtual, the near point.

25 cm, real, the far point.

25 cm, virtual, the near point.

infinity, real. the far point.

25 cm, real, the near point.

25 cm, virtual, the far point.