For each call to the following method, indicate what output is produced.

public void mystery(int n) {

print(n + " ");

if (n > 0) {

n = n - 5;

}

if (n

n = n + 7;

} else {

n = n * 2;

}

println(n);

}

mystery(8);

mystery(-3);

mystery(1);

mystery(0);

https://www.codestepby tep com problem vie, ava i else felseMysteryl ifElseMystery1 Java if/else Marty Stepp (on 2017/04/19) Language/Type: Author: For each call to the following method, indicate what output is produced public void mystery(int n) C print (n " "); if(n>0) { n=n-5; if(n