For electron diffraction, how would you calculate the spacing lattice d1 and d2 using the gradient of a radius vs 1/sqrt(accelerating voltage). Also what is the implications of the 10 Mohm resistor that is in series with the high voltage power supply:

\f1/sqrt(Power Supply) (KV) Radius (mm) = Diameter/2 0.02236067977 0.03621 0.04 0.02 0.03214 0.01825741858 0.02756 0.01690308509 0.02602 0.03 0.0158113883 0.02421 0.014907 11985 0.02353 0.01414213562 0.02111 0.02 Radius (m) = Diameter/2 0.01348399725 0.01901 0.01290994449 0.01779 0.01240347346 0.01687 0.01195228609 0.01553 0.01 0.01154700538 0.01512 0.01118033989 0.01498 0.01084652289 0.01473 0.00 0.0100 0.0125 0.0150 0.0175 0.0200 0.0225 0.01054092553 0.01433 0.01025978352 0.01387 1/sqrt(Power Supply) (V) 0.01 0.0130510MQ U R Ha 2a 2r 6,3V AC Q O G1 G2 OV AO 0...-50V Q O 0..300V 2 0 +300V 2 +4....10kV 2 Figure 3: Set-up and beam geometry for the electron beam