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For nos. 3 to 5, solve for 1:. Round eff ta 2 decimal places the final answer. {4 pts each] 3. (x+3)3(3x1)2=x3+4 4 3x +
For nos. 3 to 5, solve for 1:. Round eff ta 2 decimal places the final answer. {4 pts each] 3. (x+3)3(3x1)2=x3+4 4 3x + 1 _ 2x + 5 '6x2_4x13 5 4 3x9+x3 5. 5 6
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