for Q1 - Math 2 X Quadratic Equations Sum X Quadratic Functions Sum X New Tab x New Tab X + docs.google.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform 1. A student wanted to complete the square for the function shown below. 1 point The first few steps of their work are also shown. Which of the following options shows the next correct step? Complete the square for f (x) = 4x2 + 16x - 7. Student Work: f (x) = 4x2+16x- 7 f (x) = (4x2+ 16x) -7 f (x) = 4(x2 +4x) -7 f (x) =4(x2+4x+2-2)-7 f (x) = 4(x2 +4x+4-4)-7 HOLOC-B amazon ENG 18888 ON USMath _ X Quadratic Equations Sum X Quadratic Functions Sum X ) New lab New lab docs.google.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform 10. Choose the option that correctly identifies the values of x that solve the 1 point equation shown below. x2 - 8x - 4=0 2+41/5 4+ 15 O A . 4+ 21/5 -4+ 21/5docs.google.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform 2. A student was asked to convert the function below to vertex form by 1 point completing the square. The steps the student took are also shown below. In which step did the student make an error? y =-3x- - 6x - 5 Step I: y - -3(x2 + 2x ) - 5 Step II: y = -3(x/ + 2x + 1 - 1) -5 Step III: y = -3(x + 1)2 - 5 - 1 Step IV: y = -3(x + 1)2 - 6 Step Step II Step Ill Step IVadratic Equations Sum X Quadratic Functions Sum! New orms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform O C. UD 11. Determine the number of real, unique roots that the function below will 1 point have. f (x) =-4x2+2x+0.1 A: 2 unique real roots O B: 1 unique real root O C: no unique real roots D: impossible to say without more information 12. A right triangle is shown below. The length of the hypotenuse is 3 mm 1 point longer than double the length of x, as shown. Which of the following quadratic equations could be used to solve for the length of the hypotenuse?ork for Q1 - Math 2 X Quadratic Equations Sumi X Quadratic Functions Sumi X New Tab X New Tab X + docs.google.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform 4. Consider the factored quadratic equation shown below. Which of the 1 point following correctly states the zeros of this equation? f (x) = 3(x -5) (3x +2) x =5, x= W/N x = -5, x = WIN O A. O B. x =0, x=5, x= - WIN x =3, x=-5, x= WIN 17'C Sunny N ENG US . 108021 - Math 2 X Quadratic Equations Sum X Quadratic Functions Sum X New Tab X New Tab X docs.google.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform 5. Factor the quadratic equation shown below. 1 point x2 + 8x + 15 =0 (x + 3) (x+5)=0 (x - 3) (x +5)=0 OA . O B (x + 3) (x - 5)=0 (x - 3) (x - 5)=09. Which of the following options shows the solutions, expressed as point decimals, to the equation below? 0 = 2.5x2 + 7.5x - 1.6 x = 0.2, x = -3.2 x = -0.2, x = 3.2 O A . x = 0.5, x = -8 x = -0.5, x = 8 O 4 amazonQuadratic Equations Sum X Quadratic Functions Sum X 9 New Tab X New Tab gle.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruskuj-IN6_Q/viewform 6. Fully factor the quadratic equation shown below. point y = 2x- + 10 + 12 y = 2(x + 6)(x + 2) y-2(x + 3)(2 + 2) O A . B.O C. O D. 8. Consider the equation below. Which of the following methods would be 1 point the most suitable for determining its solutions? 0 = 1.35x2 +4.51x - 1.87 A. Factor the equation B. Complete the square C. Use the quadratic Formula D. Take the square root of both sides 9. Which of the following options shows the solutions, expressed as point decimals, to the equation below?k for Q1 - Math 2 X Quadratic Equations Sumi X Quadratic Functions Sum X New Tab X New Tab X + docs.google.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform 7. Choose the option that correctly states all roots of the function shown 1 point below. x2 - 25 =0 x =5 x = 5, x =-5 O A . O B x = 25 x = 25, x = -25 C unny amazon ON ENG USQuadratic Equations Sum X Quadratic Functions Sum X New Tab X New Tab gle.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform 12. A right triangle is shown below. The length of the hypotenuse is 3 mm 1 point longer than double the length of x, as shown. Which of the following quadratic equations could be used to solve for the length of the hypotenuse? (Hint: you'll want to recall the pythagorean theorem - it is on your formula sheet if you don't remember it). 2x + 3 X 15 mmrk for Q1 - Math 2 X Quadratic Equations Sum X Quadratic Functions Sumi X New Tab x New Tab X + docs.google.com/forms/d/e/1FAlpQLSePDnnn7S_u_JYdfbAKk3c8QDU87oEqma2ASruSkuj-IN6_Q/viewform 3. Shown below is a quadratic function in standard form. Which of the 1 point following functions is the same function, but converted to vertex form? y = x2 - 12x + 46 y = (x-6)- 10 y = (x +6) - 10 O A. O B. y =(x-6)+10 y =(x+6) +10