Question: For the circuit in the below figure, C 1 = 1 0 uF , C 2 = 5 6 uF , C 3 = 8

For the circuit in the below figure, C1=10 uF, C2=56 uF, C3=82 uC, R1=1.6 Ohm, R2=4.7 Ohm, RL =5.1 Ohm, |V1|=75 V phase 140 degrees, |V2|=15 V phase 100 degrees, and f =6 kHz. Use Node analysis to determine which of the following is true?Solve the equations to determine which of the following is true?Round up your answer to exactly two decimal points.Warning: selecting a wrong answer takes marks away.(0.625+ j2.4881) VA +(- j2.1112) VB =(-18.1744- j21.6594)-->(Equation for Node-A)(- j2.1112) VA +(0.4081+ j2.1235) VB =(-0.5542+ j3.143)-->(Equation for Node-B)(0.1099+ j1.131) VA +(- j0.5089) VB =(-15.9561+ j43.8392)-->(Equation for Node-A)(0.9091+ j0.3079) VA +(- j0.245) VB =(-6.4947+ j2.3639)-->(Equation for Node-A)(- j0.5089) VA +(0.8693+ j0.6554) VB =(-2.5+ j4.3301)-->(Equation for Node-B)None of the answers(- j0.245) VA +(1.0723+ j0.3742) VB =(-10.2606+ j28.1908)-->(Equation for

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