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For the equation of y(t) below, that is y(1)? 00 cos (1)6 (r - x) dr O cos ( 1) = - 1 O cos
For the equation of y(t) below, that is y(1)? 00 cos (1)6 (r - x) dr O cos ( 1) = - 1 O cos (0) = 1 O sin (x) =0 O sin (f) u ( t)For the equation of y(t) below, what is y(t)? 00 y(O) = cos (1) [6 (r- a) +6() ]dr -00 O cos (x) + cos (0) = -1+1=0 O cos (*) = - 1 O cos (0) + cos(x) + cos(0) =1-1+1 = 1For the expression of y(t) below, what is y(t)? y (1) = sin (D)o ( r) dr O sin (0) = 0 O - COS (D) O - sin (1) u (1) O - cos (0) = - 1
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