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For the examples below, show how binary multiplication would proceed using the final refined hardware method we discussed in class a. (-4 x -6) b.

For the examples below, show how binary multiplication would proceed using the final refined hardware method we discussed in class

a. (-4 x -6)

b. 7 x 9

c. 7 x -2

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***If the sign bit is incorrect, In hardware: sign-extend product when shifting****

Refined hardware example 2 0110 (multiplicand 6) x 0111 (multiplier-7) 00000111 (running product + multiplier) 01100111 00110011 (product after 1st iteration: add & shift) 10010011 01001000 (product after 2nd iteration: add & shift) 10101000 01010100 (product after 3rd iteration: add & shift) +0110 + 0110 0110 >00101010 (product after 4th iteration: shift) Refined hardware example 2 0110 (multiplicand 6) x 0111 (multiplier-7) 00000111 (running product + multiplier) 01100111 00110011 (product after 1st iteration: add & shift) 10010011 01001000 (product after 2nd iteration: add & shift) 10101000 01010100 (product after 3rd iteration: add & shift) +0110 + 0110 0110 >00101010 (product after 4th iteration: shift)

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