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For the following cell Pb | PbCl(s) | PbCl(soln.) | AgCl(s) | Ag the potential at 298 K is 0.490 V and the variation
For the following cell Pb | PbCl(s) | PbCl(soln.) | AgCl(s) | Ag the potential at 298 K is 0.490 V and the variation of emf with temperature is given by E = a (1.86 x 104 V K-) (T-25 K) Write the equation for the cell reaction and calculate AG, AH and AS for the reaction at 298 K.
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Chemistry The Central Science
Authors: Theodore Brown, Eugene LeMay, Bruce Bursten, Catherine Murphy, Patrick Woodward
12th edition
321696727, 978-0132175081, 978-0321696724
