For the following reaction, $44\mathrm{.}5$ grams of iron$($II$)$ chloride are allowed to react with $109$ grams of silver nitrate.

What is the maximum amount of iron$($II$)$ nitrate that can be formed?

Mass $=,g$

What is the FORMULA for the limiting reactant?

What amount of the excess reactant remains after the reaction is complete?

Mass $=,g$