For the following reaction:

CO _(g) + 2 H_{2 (g)} = CH₃OH _(g) (The = symbol represents the equilibrium arrows.)

The initial concentration of CO = 0.70 M, and the initial concentration of H₂ = 1.3 M. At equilibrium, the equilibrium concentration of CO was 0.40M. How much CO was used, and what is the equilibrium concentration of H₂?

A) There was 0.30 M of CO used, and the equilibrium concentration of H₂ was 1.00 M.

B) There was 0.30 M of CO used, and the equilibrium concentration of H₂ was 0.70 M.

C) There was 1.1 M of CO used, and the equilibrium concentration of H₂ was 0.20 M.

D) There was 1.1 M of CO used, and the equilibrium concentration of H₂ was 0 M.