For the functions f(x) = x - x - 6 and g(x) = x ? 3,(f/g)(x) would be equal to:a) (f/g) (x) = x ?

For the functions f(x) = x² - x - 6 and g(x) = x ? 3,(f/g)(x) would be equal to:a) (f/g) (x) = x³ ? 4x² ? 3x +9b) (f/g) (x) = x + 2c) (f/g) (x) = x³ + 9d) (f/g) (x)=x²-9