For the functions f(x) = x - x - 6 and g(x) = x - 3, (fg)(x) would be equal to:a) (fg)(x) = x +

For the functions f(x) = x² - x - 6 and g(x) = x - 3, (fg)(x) would be equal to:a) (fg)(x) = x + 2b) (fg)(x) = x³ + 18c) (fg)(x) = x³ ? 4x² ? 3x + 18d) (fg)(x) = x² – 18