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1) Choose the length of line 2. It should be between 20 km to 70 km and must be different from what your team-mates
1) Choose the length of line 2. It should be between 20 km to 70 km and must be different from what your team-mates have chosen. 2) Convert the positive-sequence, negative-sequence and zero-sequence reactance data to per unit using the given system base quantities (indicated in the figure). 3) Draw the (per phase) positive-sequence, negative-sequence and zero-sequence networks of the system. For synchronous machines, use subtransient reactance, X", as Xi, O Cireett Breaker 180 30 Mvar 30 Hrar 50 LI 50 M 14 12 L3 30 ar 30 Mvar 50 M 50 M 30 mvar 30 M Generator Ratings GI: 100 MVA, 13.8 kV. X" = 0.12, X2 =0.14, Xo=0.05 per unit G2: 200 MVA, I5.0 KV, X"=0.12, X2 = 0.14. Xo = (0.05 per unit The generator neutrals are solidly grounded Transformer Ratings TI: 100 MVA, 13.8 kVA A230 kV Y.X-0.1 per unit T2: 200 MVA, 15 KVA N230 kV Y, X=01 per unit The transformer neutrals are solidly grounded Transmission Line Ratings All lines: 230 KV Zi=0.08 + jo.5 /km, Za=0.2 ++jL.5 0/km Maximum MVA-400 Line length LI-15 km, L2 assigned by the instructor (20 to 70 km). L3 = 40 km. L4=15 kin. L5-50 km. Power Flow Data Bus 1: Swing (slack) bus VI 13.8 kV, 91=0. Bus 2,3,4,5, 6: Load buses Bus 7: Constant voltage magnitude bus, V, = 15 kV. Par = 180 MW, - 87 MVAR < Qo7 < + 87 MVAR System Base Quantities Shase = 100 MVA (three-phase) Viuse= 13.8 kV (line-to-line) in the zone of GI
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1 I choose L2 as 60km a round figure divisible by 10 15 and from figure it make ...Get Instant Access to Expert-Tailored Solutions
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