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For this part, please use the experimental problem inthis website: http://physics.bu.edu/~duffy/HTML5/polarized_light_curtain.html Or, http://physics.bu.edu/~duffy/HTML5/polarized_light_curtain.html The website will look something like this: I (W/m/m) Intensity vs. position

For this part, please use the experimental problem inthis website: http://physics.bu.edu/~duffy/HTML5/polarized_light_curtain.html

Or,

http://physics.bu.edu/~duffy/HTML5/polarized_light_curtain.html

The website will look something like this:

image text in transcribed
I (W/m/m) Intensity vs. position 800 Scenarios: 1 600 Correct Answers 0 400 Incorrect Answers 0 200 0 >x (cm) 0 5 10 15 20 25 30 35 40 * incident light polarizer 1 polarizer 2 polarizer 3 1 = 800.0 W/m^2 1= 400.0 W/m^2 1= ???? W/m^2 1 = 53.5 W/m^2 polarizer 1 = 171 degrees polarizer 3 = 83 degrees The goal is to figure out the angle of polarizer 2. When you know what polarizer 2 = 0 degrees it is, set the polarizer 2 slider to that value and then check your

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