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For this problem, there are 4 variables. x3 is the most significant bit (leftmost) and x0 is the least significant (rightmost). This means that m12,
For this problem, there are 4 variables. x3 is the most significant bit (leftmost) and x0 is the least significant (rightmost). This means that m12, is x3x2x1x0. Elements that are don't cares are written as dindex. For example, d12 would mean that we don't care what the output is when x3=1, x2=1,x1=0, and x0=0. Select the equation that represents the simplest POS form of (d0,m2,d5,d7,m8,d10,d13) . Again simplest POS! x2x1+x3x2x2x0(x2+x0)(x2+x1)(x1+x0)(x2+x1+x0)(x2+x1)(x3+x2+x0)(x2+x1)(x3+x2+x0)(x1+x3)(x1+x3)
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