For this problem, there are 4 variables. x3 is the most significant bit (leftmost) and x0 is the least significant (rightmost). This means that m12 is x3x2x1x0. Select the equation that represents the simplest POS form of (M4,M5,M6,M7,M14). Again simplest POS! x3x2+x3x2+x3x1+x3x0(x3+x2)(x2+x1+x0)x2x1+x3x2(x3+x2+x1)(x3+x2+x1)(x2+x1+x0)(x2+x1)(x3+x1)(x3+x2)x2+x3x1+x3x0