For this question, use the following topology. All links are 300 meters long. Propagation speed is 2x108 m/s. Transmission rates of links R3-R4, R4-R5 and R5-R6 are 8 Gbps. Transmission rates of all other links are 0.5 Gbps. There are 3 sources of traffic in this network Src1, Src2, Src3: 1) Src1 generates packets of size 3 Kb and transmits them to Dst1, 2) Src2 generates packets of size 6 Kb and transmits them to Dst2, 3) Src3 generates packets of size 3 Kb and transmits them to Dst3. Assume only these three traffics are available in the network. Each of the shared links R3-R4, R4-R5 and R5-R6 divides its bandwidth between three traffics based on the amount of traffic generated at each source. For instance, Src1 uses 2 Gbps of the bandwidth on each of these shared links. It is calculated as follows: 3Kb/(3+6+3)Kb * 8 Gbps = 2Gbps Therefore, the network is like three separate flows of traffics where each traffic uses a fixed portion of the shared links bandwidths all the time. Assume there is no processing or queuing delay. Calculate the end-to-end delay for each of three traffics in the following cases. a. Each of the 3 sources of traffic generates a message containing 1 packet. b. Each of the 3 sources of traffic generates a message containing 200 packets.