for those 4 partice hw could you help me complete them

below is my work and the red part is my mistake but i am so confuse

6 = ( 3, 2 , 516 ) ( 64) 7 = 7 101 ( 6)" = (61 = 12 why? explain 154 1 = gro ( 101, 4) 2 ) since Sis has no element of order 16 so there does not exist an element 6 E Sis, Sit 6 = ( 3, 2, 5, 6)HC ( Q, t ) be subgroup generate by finity element let H= > god ( m., Mz , .. . . MR) ecm (n1, n2 , - ...., he ) = (m> His cyclic 1 mi Mi " = N , let doged (M: ) Mi 2 Mi N ni Consider Lay ELN - H