Answered step by step
Verified Expert Solution
Question
1 Approved Answer
Formulas and General Information: Confidence interval for proportions: P + z(Sp) where z = +/- 1.96 for 95% confidence and sp = -5(1-.5) .25 N
Formulas and General Information: Confidence interval for proportions: P + z(Sp) where z = +/- 1.96 for 95% confidence and sp = -5(1-.5) .25 N N NOTE that the numerator here is different than the book! Use .5 for p in the numerator here instead as discussed in lecture * *#** For means: X + t(sx) where sx = S VN - 1 and of for the t-distribution = N-1\ftistics Viewer orm Insert Format Analyze Graphs Utilities Extensions Window Help completed, father Descriptives Statistic Std. Error Highest year of school Mean 14.22 074 completed 95% Confidence Interval Lower Bound 14.07 for Mean Upper Bound 14.36 5% Trimmed Mean 14.29 Median 14.00 Variance 8.599 Std. Deviation 2.932 Minimum 0 Maximum 20 Range 20 Interquartile Range 4 Skewness -.545 062 Kurtosis 1.742 124 Highest year school Mean 11.91 096 completed, mother 95% Confidence Interval Lower Bound 11.72 for Mean Upper Bound 12.10 3 O WW hpHW3.pdf X Dashboard (45 unread) - dnabomb2131 x VM du/portal/webclient/#/desktop Course Hero Yahoo Mail i Gmail Mail - Weidenkopf,.. @ UCDAccess - Univer... Canvas! C Viewer Insert Format Analyze Graphs Utilities Extensions Window Help Q 5% Trimmed Mean 12.13 Median 12.00 Variance 14.516 Std. Deviation 3.810 Minimum Maximum 20 Range 20 Interquartile Range 3 Skewness -.956 062 Kurtosis 1.442 124 ghest year school Mean 11.90 106 ompleted, father 95% Confidence Interval Lower Bound 11.70 for Mean Upper Bound 12:11 5% Trimmed Mean 12.08 Median 12.00 Variance 17.425 Std. Deviation 4.174 Minimum 0 Maximum 20 Range 20 Interquartile Range 5 IBM SPSS O Hi W hpver ert Format Analyze Graphs Utilities Extensions Window Help Minimum Maximum 20 Range 20 Interquartile Range 3 Skewness 956 062 Kurtosis 1 442 124 lest year school Mean 11.90 106 pleted, father 95% Confidence Interval Lower Bound 11.70 for Mean Upper Bound 12 1 1 5% Trimmed Mean 12.08 Median 12.00 Variance 17 425 Std. Deviation 4.174 Minimum 0 Maximum 20 Range 20 Interquartile Range 5 Skewness -.671 062 Kurtosis 641 124 IBM O E O hp
Step by Step Solution
There are 3 Steps involved in it
Step: 1
Get Instant Access to Expert-Tailored Solutions
See step-by-step solutions with expert insights and AI powered tools for academic success
Step: 2
Step: 3
Ace Your Homework with AI
Get the answers you need in no time with our AI-driven, step-by-step assistance
Get Started