\fQuestion 3 (1 point) 6 4 24 :i1 is divided by hag'31:, can be written in the form The restrictions on 33, when a: y C. The possible value(s) for Ccan be selected from the table below. Code Possibilities for C 1 -6 2 O 3 1 4 -6, 0 5 -6, 1 6 O, 1 7 -6, 0, 1 The code for C; is Question 4 (1 point) When the rational expression to I is simplified, the equivalent expression can be written in the form x+1, x #-2. Expressions for A and B that would correctly complete the original rational expression can be selected from the table below. Code Possibilities for A Code Possibilities for B 1 5x + 5 4 5 2 x2 + 3x + 2 5 X 3 x2 + x 6 x + 2 To form the original rational expression the code for A and code of B written in the form A, B with no spaces would be: A/Question 5 (1 point) 7p2 The simplified product of 5m'n3 10min and p5 -, where m * 0, n * 0 and p * 0, can be represented by AmnB 2pc where A, B, and C represent single-digit numbers. In the simplified product AmnB 2pc -, the values of A, B, and C, in that order are _. (Record the value of A in blank #1, the value of Bin blank #2, and the value of Cin blank #3.) Blank # 1 A Blank # 2 A Blank # 3Question 6 (1 point} The largest nonpermissible value for :1} in the expression 4:32 8:1: _ 10:1: + 5:1:2 25+5m ' 4$+2G is :e/ The dimensions of a rectangle are represented by rational expressions, as shown in the diagram below. 6 x+2 x -+ 2x 2x Determine the area, for all permissible values of x. (Record your answer in the space below. Do not include units in your answer) AQuestion 8 (1 point] 2331 . 5:1: m Is subtracted from 336' the fully simplified expression is equal to Question 9 (1 point) 3 7x When 20x is added to Q , the numerator is 6 + 35, and the denominator isQuestion 10 (1 point] A student was asked to simplify and state the non permissible values for the 4 following rational expression: +. 4x-12 x-3 The student's work is shown below. 1 4 S 1 + rep 4112 13 _ 1 4 Shep2. _ 4(13-13 \"9 ' ac330:4) 1 S 4: = ,x3 \"'9 (at30:4) Identifyr the Step where the student made their first error. The student's first error occurred in Step [ ] l, Question 11 (1 point) The value of x that would give an extraneous solution, x - - 1 is X = Question 12 (1 point) The value of 2, for ac 3x+5 , that makes the two rational expressions 3x+1 and equal to each other isQuestion 13 (1 point] 3 . 5 When 8332+43: Is added to 43221 , the sum can be expressed as b$+c 4a:(2:r:1)(2ml1)' The values of b and c, in that order are _____ and (Record the value of bin blank #1 and the value of c in blank #2.) Blank # 1 a), Blank # 2 9/ Question 14 {1 point] A student solved a rational equation using the steps shown below. Step1 x(x1)2(x+l)= 2 Step: xz-x-Zx2=2 Step3 x2_3x_4=0 Step4 (x4)(x+l)= 0 Step5 x=L 4 The student's first recorded error is in step ____. _'v Question 15 (1 point) Jerryjogged 9 km in an hour. He covered the last 4 km at a speed that was 2 kmfh slower than his speed over the first 5 km. To help organize the above information a student created the following table and rational equation. D v (=2 v First5km 5 x 2 X Last4km 4 x-2 i x2 _+i=1 x x2 Based on the above information, Jerry's speed over the last 4 km would be Q/ km/h