\fQuestion 7 Use the Intermediate Value Theorem to show that the given function has a zero in the interval [0, 2]. 2puints f(35) :55'2 +5$72 How Did I D09 f (m) Click lcir List ' on the interval [0, 2]. f (0') : Number f (2) = Number By the Intermediate Value Theorem, there is a value c in [0, 2] such that f(c) : 0, since f (0) Click for List ' 0 and f (2) Click for List ' 0