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fRewrite F(a) as F(u) using a substitution of variables. F(a) = S (2x + 5) sin (a2 + 5x) dx O F(u) = - S
\fRewrite F(a) as F(u) using a substitution of variables. F(a) = S (2x + 5) sin (a2 + 5x) dx O F(u) = - S sinu du O F(u) = f usin u du O F(u) = - S cosu du O F(u) = f sinu duRewrite F(a) as F(u) using a substitution of variables. F(a) = S (2x + 5) sin (a2 + 5x) dx O F(u) = - S sinu du O F(u) = f usin u du O F(u) = - S cosu du O F(u) = f sinu duRewrite F(a) as F(u) using a substitution of variables. F(x) = S 10r+3 da 512-3147 O F(u) = - S1 du O F(u) = S du O F(u) = S 2 du O F(u) = S1 du\fWhat is F(x) - Jx2 va-3 - 4dax? O F(a) = 2 (23 - 4) O F(a) = 2 (23 - 4) 2 + C O F(*) = - 4 ) + C O F(x) = = (23 -4) 2 +0\fAn object with an initial velocity of v(0) = 3 has an acceleration of a(t) = 5 + 6t. What is its velocity at t = 5? O 35 O 97 O 100 O 103What is the Riemann sum that represents the illustration shown? The function is f(a) = 3x + 1. -NWACO 4005 2 3 Created with a trial version of Advanc 5 o ( 3x2 + 1) i= 1 3 o (3xi + 1) . Axi 5 o (3x; - 1) . Ari i=1 5 O (3x; + 1) . AriWhich integral would represent the area shown? The function is f(a) = -(a - 1) + 2. 5 4 3 2 Created with a trial version of Advan o so - ( x - 1) 3 + 2 da o s [(x -1)3] da of(x-1)3) da o s2 [- (x -1)3 +2 de
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