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From previous integration techniques we know that [sec(t) dt = In| sec(t) + tan(t)|. Use this to evaluate the trig integral from Part 1
From previous integration techniques we know that [sec(t) dt = In| sec(t) + tan(t)|. Use this to evaluate the trig integral from Part 1 and then substitute back to get the final result in terms of x. To substitute back in terms of x, you would use tan(t) = sec(t) = The final result of the integration would then be 2 x+15 dx = +C
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