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From the definition of the definite integral, we have 6k limn00-1 (+ sin (6T)) k= A. f (2x + sin(2x))dx 6 B. f (x

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From the definition of the definite integral, we have 6k limn00-1 (+ sin (6T)) k= A. f (2x + sin(2x))dx 6 B. f (x + sin x)dx 3. Oc. (x + sin(2x))dx 3 OD. f (2x + sin(2x))dx .6 OE. (x+sin(2x))dx =

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